...calculate the Reynolds Number?
...calculated the lift coefficient?
...read the polar diagrams?
...plot an airfoil from coordinates?
...find the angle of attack of my wing?
...determine the timing of my engine?
The Reynolds number is an important value for the behavior of the flow, and especially the boundary layer. Flows with the same Reynolds number behave similar. This number can be calculated by the exact formula, given in the glossary. If medium accuracy is sufficient, the Reynolds number can be approximately calculated by the following formula.

where:

The Reynolds number is based on a length, which is usually the chord length of an airfoil (in two dimensions) or the chord length of a wing. Because the chord length of a wing may vary from root to tip, a mean aerodynamic chord length is used to define the Reynolds number for a wing. Reynolds numbers are also used for other objects, like the flows in tubes, where other length scales are used. For the flow in tubes or around a sphere, the diameter is used.
Example:  A full scale aircraft flies at a speed of 100 m/s and has a tip chord of 1 meter an a root chord of 2.5 meters. The Reynolds number of the flow at the tip station is approximately 100 * 1.0 * 70000 = 7 Millions, at the root the Reynolds number is 17.5 Millions. A 1/4 scale model would fly at roughly 40 m/s and thus would have a tip Reynolds number of 40 * 1.0/4 * 70000 = 0.7 Millions, which is only 1/10 of the full scale plane. Because of this difference, we have to expect a different flow behavior in terms of drag and stall characteristics. 

The lift coefficient is a relative measure for the lift of an airfoil or wing. It is used for comparisons of wings of different size and at different conditions (speed, density of air). Similar coefficients are also used for drag and moment. Its definition reads:

where:

Example:  We want to build a heavy airplane model which will have an assumed mass
of 10.0 kg. Since it is a scale model, its wing area is already defined to
be 0.8 m². From our experience with similar models, we have chosen an
airfoil, and want to know, how slow we can come in for landing.
The wing has to lift the weight of the model (mass*9.81) and we hope to flare out at a speed of 10 m/s. Thus, the necessary lift coefficient would be 10.0*9.81/(1.225/2 * 10*10 * 0.8) = 2.0. If we look into the polar charts for the selected airfoil, we find, that its maximum lift coefficient is about 1.5 and thus lower, than the required value of 2.0. This means, we cannot fly as slow as we wanted. If we could reduce the weight to 7.5 kg, the required lift coefficient would go down to 1.5, which is what we can achieve with the selected airfoil. 

last modification of this page: 05.05.02
[Back to Home Page] [Index of all Pages] Suggestions?
Corrections? Remarks? e Martin Hepperle.
As I get quite a number of messages, it might take some time until you receive an
answer and in some cases I get lost in the flood and you may even receive no answer at
all. I apologize for this, and if you have not lost patience, you might want to send me a
copy of your email after a month or so.
Copyright 19862001 Martin Hepperle
You may use the data given in this document for your personal use. If you use this
document for a publication, you have to cite the source. A publication of a recompilation
of the given material is not allowed, if the resulting product is sold for more than the
production costs. Some names appearing on this web are trademarks or registered names whose rights belong to their owners, even if not explicitely stated. This document
can be found by navigating from the Web site http://www.MHAeroTools.de/